算法编程实战

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eg2.写一个函数printN，打印出从1到N

#include<stdio.h>

void printN1(int n);

void printN2(int n);

void printN2(int n){

if(n){

printN2(n-1);

printf("%-4d ", n);

}

}

void printN1(int n){

int i;

for(i = 0; i < n; i++){

printf("%-4d ", i+1);

}

}

void main(void){

int n;

printf("请输入一个正整数：");

scanf("%d", &n);

printN1(n);

printN2(n);

}

eg3.写程序计算给定多项式在给定点x处的值

#include<stdio.h>

#include<math.h>

#define N 3

double fun1(double a[], int n, double x);

double fun2(double a[], int n, double x);

double fun2(double a[], int n, double x){

double y = a[n];

int i;

for(i = n; i > 0; i--){

y = a[i-1]+ y*x;

}

return y;

}

double fun1(double a[], int n, double x){

double y = 0;

int i;

for(i = 0; i <= n; i++){

y += a[i]*pow(x, i);

}

return y;

}

void main(void){

double a[N+1];

int i;

double x;

printf("请输入多项式的系数(次幂逐渐增大,最高次幂为%d)：", N);

for(i = 0; i < N+1; i++){

scanf("%lf", &a[i]);

}

printf("请输入x的值：");

scanf("%lf", &x);

printf("fun1函数在点%lf处的值为：%lf\n", x, fun1(a, N, x));

printf("fun2函数在点%lf处的值为：%lf\n", x, fun2(a, N, x));

}

最大子列和问题(遗留，分而治之)

#include<stdio.h>

#define N 8

void inputData(int a[], int n);

int maxSubseqSum1(int a[], int n);

int maxSubseqSum2(int a[], int n);

int maxSubseqSum2(int a[], int n);

int maxSubseqSum2(int a[], int n){

int i;

int j;

int k;

int sum;

int max = 0;

for(i = 0; i < n; i++){

sum = 0;

for(j = i; j < n; j++){

sum+=a[j];

if(sum > max){

max = sum;

}

}

}

return max;

}

int maxSubseqSum1(int a[], int n){

int i;

int j;

int k;

int sum;

int max = 0;

for(i = 0; i < n; i++){

for(j = i; j < n; j++){

sum = 0;

for(k = i; k < j; k++){

sum+=a[k];

}

if(sum > max){

max = sum;

}

}

}

return max;

}

void inputData(int a[], int n){

int i;

printf("请输入%d个整型数据：", N);

for(i = 0; i < n; i++){

scanf("%d", &a[i]);

}

}

void main(void){

int a[N];

inputData(a, N);

printf("最大子列和为：%d\n", maxSubseqSum1(a, N));

printf("最大子列和为：%d\n", maxSubseqSum2(a, N));

}

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