谷歌身份验证器小白篇
携带驾驶证原件和身份证,可能需要身份验证 #生活常识# #日常生活小窍门# #出行建议# #租车注意事项#
今天小白尝试了下谷歌身份验证器,记录下体会,谷歌身份验证器主要采用的是用户端跟后端独立生成验证码。验证码生成规则中有两个东西非常重要,一个是秘钥,一个时间,如果其中任意一个对不上,都会导致前后端验证码对不上。因此为保证手机时间准确性,手机时间设置成网络同步。手机搜索安装谷歌身份验证器,添加秘钥。
后端代码网上很多,随便找了一个,测试可用
package com.bessky.hrmis.common.rbac.encrypt;
import java.security.InvalidKeyException;
import java.security.NoSuchAlgorithmException;
import java.security.SecureRandom;
import javax.crypto.Mac;
import javax.crypto.spec.SecretKeySpec;
import org.apache.commons.codec.binary.Base32;
import org.apache.commons.codec.binary.Base64;
/**
*
*
* google身份验证器,java服务端实现
*/
public class GoogleAuthenticator {
// 生成的key长度( Generate secret key length)
public static final int SECRET_SIZE = 10;
public static final String SEED = "g8GjEvTbW5oVSV7avL47357438reyhreyuryetredLDVKs2m0QN7vxRs2im5MDaNCWGmcD2rvcZx";
// Java实现随机数算法
public static final String RANDOM_NUMBER_ALGORITHM = "SHA1PRNG";
// 最多可偏移的时间
int window_size = 10; // default 3 - max 17
/**
* set the windows size. This is an integer value representing the number of
* 30 second windows we allow The bigger the window, the more tolerant of
* clock skew we are.
*
* @param s
* window size - must be >=1 and <=17. Other values are ignored
*/
public void setWindowSize(int s) {
if (s >= 1 && s <= 17)
window_size = s;
}
/**
* Generate a random secret key. This must be saved by the server and
* associated with the users account to verify the code displayed by Google
* Authenticator. The user must register this secret on their device.
* 生成一个随机秘钥
*
* @return secret key
*/
public static String generateSecretKey() {
SecureRandom sr = null;
try {
sr = SecureRandom.getInstance(RANDOM_NUMBER_ALGORITHM);
sr.setSeed(Base64.decodeBase64(SEED.getBytes()));
byte[] buffer = sr.generateSeed(SECRET_SIZE);
Base32 codec = new Base32();
byte[] bEncodedKey = codec.encode(buffer);
String encodedKey = new String(bEncodedKey);
return encodedKey;
} catch (NoSuchAlgorithmException e) {
// should never occur... configuration error
}
return null;
}
/**
* 生成一个google身份验证器,识别的字符串,只需要把该方法返回值生成二维码扫描就可以了。
* @param label
* 标签
* @param user
* 账号
* @param secret
* 密钥
* @return
*/
public static String getQRBarcode(String label, String user, String secret) {
String format = "otpauth://totp/%s:%s?secret=%s";
return String.format(format, label, user, secret);
}
/**
* 生成一个google身份验证器,识别的字符串,只需要把该方法返回值生成二维码扫描就可以了。
*
* @param user
* 账号
* @param secret
* 密钥
* @return
*/
public static String getQRBarcode(String user, String secret) {
String format = "otpauth://totp/%s?secret=%s";
return String.format(format, user, secret);
}
/**
* Check the code entered by the user to see if it is valid 验证code是否合法
*
* @param secret
* The users secret.
* @param code
* The code displayed on the users device
* @param t
* The time in msec (System.currentTimeMillis() for example)
* @return
*/
public boolean check_code(String secret, long code, long timeMsec) {
if(secret == null || "".equals(secret))
{
return false;
}
Base32 codec = new Base32();
byte[] decodedKey = codec.decode(secret);
// convert unix msec time into a 30 second "window"
// this is per the TOTP spec (see the RFC for details)
long t = (timeMsec / 1000L) / 30L;
// Window is used to check codes generated in the near past.
// You can use this value to tune how far you're willing to go.
for (int i = -window_size; i <= window_size; ++i) {
long hash;
try {
hash = verify_code(decodedKey, t + i);
} catch (Exception e) {
// Yes, this is bad form - but
// the exceptions thrown would be rare and a static
// configuration problem
e.printStackTrace();
throw new RuntimeException(e.getMessage());
// return false;
}
if (hash == code) {
return true;
}
}
// The validation code is invalid.
return false;
}
private static int verify_code(byte[] key, long t) throws NoSuchAlgorithmException, InvalidKeyException {
byte[] data = new byte[8];
long value = t;
for (int i = 8; i-- > 0; value >>>= 8) {
data[i] = (byte) value;
}
SecretKeySpec signKey = new SecretKeySpec(key, "HmacSHA1");
Mac mac = Mac.getInstance("HmacSHA1");
mac.init(signKey);
byte[] hash = mac.doFinal(data);
int offset = hash[20 - 1] & 0xF;
// We're using a long because Java hasn't got unsigned int.
long truncatedHash = 0;
for (int i = 0; i < 4; ++i) {
truncatedHash <<= 8;
// We are dealing with signed bytes:
// we just keep the first byte.
truncatedHash |= (hash[offset + i] & 0xFF);
}
truncatedHash &= 0x7FFFFFFF;
truncatedHash %= 1000000;
return (int) truncatedHash;
}
}
网址:谷歌身份验证器小白篇 https://www.yuejiaxmz.com/news/view/450599
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